The total is a half Jane T total square, and so that's a huff to acceleration due to gravity nine for 8 m per square. Original position is 1.985 seconds, and hence we can calculate the distance of the tuning fork has fallen in that time. So a total time for the frequency off 485 hertz could be absolved at the tuning forks.
And so we get the total time off one 0.9 eight five seconds. And Sir TKs, we can't need to be one for 90 seconds and the turn time for the sound wave 0.58 seconds.
That's the time that the wave has returned to its original position. But what we have to remember is that the folk continues to fall while the sound of tons, so the total time with quality total is equal to the time of the full. It's traveling at a constant speed and the 40 m per second against this time 0.0 53 eight seconds with the sound turned to original position. It has to come up 18.3 m over the speed of sound. Subsequent return is equal to the distance. So the time through a ton, we'll call it T. So after it has fallen 18.3 m, the sound wave has to return a distance to its original point off each 1.2 m. Second times this value T F 1.9 30 will square, and so the tuning folk covers a distance while falling off 18 going to be meters. Yes, quit and so that's a huff In 29.8 reaches square. Now the distance covered in this time recorded, the one is equal to a house G. 40 time of 1.93 seconds to in time, and they had a frequency of Florida 85 huts. Rearranging above is one or 90 seconds to the training for the tuning forecaster.
512 HZ TUNING FORK FULL
What? So if we release equation, we can solve for the time of full Teoh TF. So we open out the secretion of the more we get for its five times 300 40 bless 485 times nine 0.8 multiplied by T s. And the speed off the training smoke is minus its acceleration nine point 8 m per second squared downwards, much of bad by the time over which it has fallen. You suppressed our units here over 320 minus. Original frequencies 512 HUD's into speed of sound. So we want the observed frequency at its initial position to be 485 huts and the tuning forks. Yes, where the speed of sound in A and B s is the speed of the tuning fork after it has fallen a certain distance.
Acts like two point sources and beautifully shows wave like interference analogous to light and sound. So since the tuning fork is in motion, we can use the doctor equation that the pattern frequency is equal to the frequency of the training for if into the minus the over V minus. 512 Hz (C) tuning fork interacting with a water surface.
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